Question

Find the domain of f(x)=square root x^2−36.

Select one:
a. x≥6 or x≤−6
b. x≥36
c. all real numbers
d. x≥6

Answer 1

`f(x)= \sqrt{x^(2)-36} \\ \\ D: x^(2)-36 \geq 0 \\ \\ (x-6)(x+6) \geq 0 \\ \\ x+6=0 \ \vee \ x-6=0 \\ \\ x=-6 \ \vee \ x=6 \\ \\ x\in (-\infty,-6 ) \ \cup \ (6,+\infty)`