Question

50 < 2x + 10 and 2x + 10 < 110 solve for x in this inequality

Answer 1

`\begin{gathered} 50<2x+10 \\ \text{Solving for x:} \\ \text{Subtract 10 from both sides:} \\ 50-10<2x+10-10 \\ 40<2x \\ \text{Divide both sides by 2:} \\ (40)/(2)<(2x)/(2) \\ 2020 \end{gathered}`