Question

What is the center of a circle given by the equation (x + 5) squared + (y - 8) squared equals one?

Answer 1

`(x-h)^2+(y-k)^2=r^2\\ \text{center}=(h,k)\\\\ (x+5)^2+(y-8)^2=1\\ \text{center}=(-5,8)`

Answer 2

`(x+5)^2 +(y-8)^2 = 1`


`(x-h)^2 +(y-k)^2 = r^2`

then the center of the circle is


`(h,k)`

So the center of the circle for your question would be:

(-5, 8)