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Using the completing-the-square method, rewrite f(x) = x2 − 6x + 2 in vertex form. a. f(x) = (x-3)^2 b. f(x) = (x-3)^2 + 2 c. f(x) = (x-3)^2 - 7 d. f(x) = (x-3)^2 + 9

Using the completing-the-square method, rewrite f(x) = x2 − 6x + 2 in vertex form. a. f(x) = (x-3)^2 b. f(x) = (x-3)^2 + 2 c. f(x) = (x-3)^2 - 7 d. f(x) = (x-3)^2 + 9
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Using the completing-the-square method, rewrite f(x) = x2 − 6x + 2 in vertex form.

a. f(x) = (x-3)^2
b. f(x) = (x-3)^2 + 2
c. f(x) = (x-3)^2 - 7
d. f(x) = (x-3)^2 + 9

User Zhongqi
by
8.8k points

1 Answer

2 votes

x^2-6x+2= \\ (x^2-6x+9)-9+2= \\ (x-3)^2-7

The answer is C. f(x)=(x-3)²-7.
User Jlents
by
8.3k points
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