solve your system of equations.
3x+2y=8;2x+3y=2
Solve 3x+2y=8 for x:
3x+2y+−2y=8+−2y(Add -2y to both sides)
3x=−2y+8
3x/3=−2y+83(Divide both sides by 3)
x=−2/3y+8/3
Substitute (−2/3y+8/3) for x in 2x+3y=2:
2x+3y=2
2(−2/3y+8/3)+3y=2
5/3y+16/3=2(Simplify both sides of the equation)
5/3y+16/3+−16/3=2+−16/3(Add (-16)/3 to both sides)
5/3y=−10/3
5/3y5/3=−10/35/3(Divide both sides by 5/3)
y=−2
Substitute (−2) for y in x=−2/3y+8/3:
x=−23y+83
x=−23(−2)+83
x=4(Simplify both sides of the equation)
Answer is A)