Question

Solve by using the perfect squares method. x2 + 4x + 4 = 0

a. 2
b. –2
c. 4
d. –4

Answer 1

`a^2+2ab+b^2=(a+b)^2 \\ \Downarrow \\ x^2+4x+4=x^2 + 2 * 2 * x +2^2=(x+2)^2 \\ \\ x^2+4x+4=0 \\ (x+2)^2=0 \\ x+2=0 \\ x=-2`

The answer is B.

Answer 2

solve your equation step-by-step.

x2+4x+4=0

Factor left side of equation.

(x+2)(x+2)=0

Set factors equal to 0.

x+2=0

or

x+2=0


x=−2