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What is the factorization of 216x^12 – 64? a. (6x^3 – 4)(36x^6 + 24x^3 + 16) b. (6x^3 – 4)(36x^9 + 24x^3 + 16) c. (6x^4 – 4)(36x^8 + 24x^4 + 16) d. (6x^4 – 4)(36x^12 + 24x^4 + 16)
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5 votes
What is the factorization of 216x^12 – 64?

a. (6x^3 – 4)(36x^6 + 24x^3 + 16)
b. (6x^3 – 4)(36x^9 + 24x^3 + 16)
c. (6x^4 – 4)(36x^8 + 24x^4 + 16)
d. (6x^4 – 4)(36x^12 + 24x^4 + 16)

User Constantina
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2 Answers

4 votes

Answer:c on edge

Explanation:

just did it on test

User Rjray
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8.2k points
7 votes

216x^(12)-64=8(27x^(12) - 8) = 8[(3x^(4))^(3) - 2^(3)] = \\ \\ =8(3x^(4)-2)(9x^(8) +6x^(4) +4) = 2(3x^(4)-2)*4(9x^(8)+6x^(4)+4)= \\ \\ (6x^(4)-4)(36x^(8)+24x^(4)+16)

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a^3-b^3=(a-b)(a^2+ab+b^2)

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User Macshome
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