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1+cos(8x)= a. 4cos(2x) b. 2sin^2(4x) C.4sin(2x) D.2cos^(4x)
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5 votes
1+cos(8x)=
a. 4cos(2x)
b. 2sin^2(4x) C.4sin(2x) D.2cos^(4x)

User Aawaz Gyawali
by
8.7k points

2 Answers

3 votes

Answer:

2Cos^2(4x)

Explanation:

Apex

User Sylvain Lesage
by
7.7k points
1 vote

cos^2(x)+sin^2(x)=1 \\ 1=cos^2(4x)+sin^2(4x) \\ \\ cos(2x)=cos^2(x)-sin^2(x) \\ cos(8x)=cos(4 * 2x)=cos^2(4x)-sin^2(4x) \\ \\ \\ 1+cos(8x)=cos^2(4x)+sin^2(4x) +cos^2(4x)-sin^2(4x) \\ cos^2(4x)+cos^2(4x)=2cos^2(4x)

D.2cos^(4x)

User Eliseo Soto
by
8.1k points
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User Ali B
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