Question

Solve for x: −5|x + 1| = 10

Answer 1

`x+1=0 \\ \\ x=-1 \\ \\ \pmb 1^(o) \\ \\ x\in (-\infty,-1) \\ \\ -5|x+1|=10 \\ \\ 5(x+1)=10 \\ \\ 5x+5=10 \\ \\ 5x=5 \\ \\ x=1 \\ot\in D \\ \\ \pmb 2^(o) \\ \\ x\in [-1, +\infty) \\ \\ -5|x+1|=10 \\ \\ -5(x+1)=10 \\ \\ -5x-5=10 \\ \\ -5x=15 \\ \\ x=-3 \\ot\in D \\ \\ x\\ot\in \Re`

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Answer 2

solve step-by-step.

−5(|x+1|)=10

Divide both sides by -5.

−5(|x+1|)/−5=10/−5

|x+1|=−2

Solve Absolute Value.

|x+1|=−2

No solutions. (Absolute value cannot be less than 0.)