1 Answer

Delby · Answer 1 · 2016-11-16T03:06:22+0000

The reaction:

$^(14) _7 N + ^1 _0n \to ^1 _1 H+ ^A _Z X$

The sum of the mass numbers and the sum of the atomic numbers must be the same on both sides of the reaction.

The mass numbers:

$14+1=1+A \\ 14+1-1=A \\ A=14$

The atomic numbers:

$7+0=1+Z \\ 7+0-1=Z \\ Z=6$

The formed nucleus has the atomic number 6, so it's a nucleus of carbon.

$^(14) _7 N + ^1 _0 n \to ^1 _1 H + \boxed{^(14) _6 C}$
A nucleus of carbon-14 is formed.

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