Question

Given that cos (x) = 1/3, find sin (90 - x)

Answer 1

`90а= ( \pi )/(2) \\ sin(90а-x)=sin (( \pi )/(2)-x)=cos (x) \\ cos(x)= (1)/(3) \\ sin(x)= (1)/(3) \approx0.33333 \\ x=19а`

Answer 2

`sin((A - B)) \equiv sin(A)cos(B) - cos(A)sin(B) \\\\ \therefore sin((90 - x))\\ = sin((90))cos((x)) - cos((90))sin((x)) \\ = (1)cos((x)) - (0)sin((x)) \\ = cos(x) - 0 \\ = cos(x) \\ = (1)/(3)`