Question

Hello! I was wondering if if you could solve this becuseI I just want to check my work because I already did it and I want to be sure it's right.

Answer 1

`p^4+3p^2`

Step-by-step explanation

`\begin{gathered} (2p^5+6p^3)/(2p) \\ \end{gathered}`

Step 1

factorize the numerator

`\begin{gathered} (2p^5+6p^3)/(2p)=(2p^5+2\cdot3p^3)/(2p) \\ (2p^5+6p^3)/(2p)=(2p^(4+1)+2\cdot3p^(2+1))/(2p) \\ (2p^5+6p^3)/(2p)=(2pp^4+2p\cdot3p^2)/(2p) \\ (2p^5+6p^3)/(2p)=(2p(p^4+3p^2))/(2p) \end{gathered}`

Step 2

the 2p in the numerator cancels the 2p in the denominator,so

`\begin{gathered} (2p(p^4+3p^2))/(2p)=p^4+3p^2 \\ \\ p^4+3p^2 \end{gathered}`

I hope this helps you