Question

Simplify the expression: cot x sin x - sin quantity pi divided by two minus x. + cos x

Answer 1

`\cot x= (\cos x)/(\sin x) \\ \sin ( ( \pi )/(2)-x)=\cos x \\ \\ \cot x \sin x-\sin( ( \pi )/(2)-x) +\cos x= \\ (\cos x)/(\sin x) \sin x- \cos x+ \cos x= \\ \cos x- \cos x+ \cos x = \\ \cos x \\ \\ \ \cot x \sin x-\sin( ( \pi )/(2)-x) +\cos x= \cos x`