Question

I need to know how to do this step by step. I'm having trouble with figuring out what comes first and What do I have to do next when solving the problem

Answer 1

The given inequality is

`3y\leq2y+3`

First, we need to isolate y

To do that we want to move 2y from the right side to the left side, then

To do that subtract 2y from 3y and subtract 2y from (2y + 3)

`3y-2y\leq2y-2y+3`

Since 3y - 2y = 1y

Since 2y - 2y = 0

`\begin{gathered} 3y-2y\leq(2y-2y)+3 \\ 1y\leq0+3 \end{gathered}`

Since 0 + 3 = 3

Then the answer is

`\begin{gathered} 1y\leq3 \\ y\leq3 \end{gathered}`

The answer is B