Question

Which of the following functions has the largest value when x = 4?

e(x) = x2 + 6x + 21
m(x) = 8x
v(x) = 31x

Answer 1

`e(4)=4^2+6 * 4+21=16+24+21=61 \\ \\ m(4)=8 * 4=32 \\ \\ v(4)=31 * 4=124`

v(x) has the largest value when x=4.

Answer 2

Answer:
`v(x)=31x`

Explanation:

Given Functions:
`e(x)=x^2+6x+21`

`m(x)=8x\\\\v(x)=31x`

At x=4

`e(4)=(4)^2+6(4)+21\\=16+24+21=61\\\\m(4)=8(4)=32\\\\v(4)=31(4)=124`

here we can see v(4) has the largest value of 124 at x=4 .

Therefore,
`v(x)=31x` is the function which has the largest value at x=4.