Solve for m in E=1/2mv²+mgh

asked May 23, 2015 31.4k views

1 vote

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$E= (1)/(2)mv^2+mgh \ \ / \cdot 2\\ \\ 2 \cdot (1)/(2)mv^2+ 2\cdotmgh = 2\cdot E\\ \\ mv^2+2mgh= 2E \\ \\m(v ^2+2gh)= 2E \\ \\ m=(2E)/(v ^2+2gh)$

ModusCell answered May 23, 2015

7.0k points

4 votes

$E= (1)/(2) mv^2+mgh\ /\cdot2\\\\2E=mv^2+2mgh\\\\2E=m(v^2+2gh)\ /:(v^2+2gh)\\\\m= (2E)/(v^2+2gh)$

David Florez answered May 29, 2015

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