Question

Each month, a retail store awards a blue ribbon to its employee of the month. The probability that Chloe is the employee of the month is 29% in January and 49% in February. What is the probability that she is awarded a blue ribbon in both January and February?

Answer 1

1421 / 100 = 14.21%

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Answer 2

`0.1421\ or\ 14.21\%`

Step-by-step explanation:

The probability that Chloe is the employee of the month in January is 29% or 0.29

i.e
`P(J)=0.29`

The probability that Chloe is the employee of the month in February is 49% or 0.49

i.e
`P(F)=0.49`

As both of the events are independent, so

`P(J\ and\ F)=P(J)\cdot P(F)`

`=0.29* 0.49`

`=0.1421=14.21\%`

Therefore, the probability that Chloe is awarded a blue ribbon in both January and February is 0.1421 or 14.21%