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Use long division. (30x³+4x²-150)÷(3x-5)

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asked Sep 8, 2015 10.1k views

4 votes

Use long division.
(30x³+4x²-150)÷(3x-5)

Mathematics
high-school

Charles Gargent asked

by Charles Gargent

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$30x^3+4x^2-150=10x^2(3x-5)+18x(3x-5)+30(3x-5)=\\ \\=(3x-5)(10x^2+18x+30)\\\\ \\ (30x^3+4x^2-150):(3x-5)= ((3x-5)(10x^2+18x+30))/(3x-5) =10x^2+18x+30$

Pep answered Sep 14, 2015

by Pep

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Use long division. (30x³+4x²-150)÷(3x-5)

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