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Solve 3x+2y=7 and x-4y=-21 by using substitution

User Taoufik A
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3x+2y=7 \\ x-4y=-21 \\ \\ \hbox{solve the second equation for x:} \\ x-4y=-21 \\ x=4y-21 \\ \\ \hbox{substitute 4y-21 for x in the first equation:} \\ 3(4y-21)+2y=7 \\ 12y-63+2y=7 \\ 14y=7+63 \\ 14y=70 \\ y=(70)/(14) \\ y=5 \\ \\ x=4y-21=4 * 5-21=20-21=-1 \\ \\ \boxed{(x,y)=(-1,5)}
User Quickern
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