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Verify the identity:

(1+tan^2u)(1-sin^2u)=1

User Beertastic
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1 Answer

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=> The first expression on the left: (1 + tan²)

we know that tangent = sin/cos
so tan² = sin²/cos²
the expression is (1 + sin²/cos²)

=> The second expression on the left: (1 - sin²)

we know that (sin² + cos²) = 1
subtract sin² from each side,
and we have (1 - sin²) = (cos²)

=> Multiply the massaged form of the two expressions:

(1 + tan²) (1 - sin²) = (1 + sin²/cos²) (cos²) = (cos² + sin²) = 1 qed


User GaurabDahal
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