Question

Could someone guide me through this one plz A system of two equations is shown below: Equation C: a = 4b + 5 Equation D: a = 6b − 2 What value of a can be substituted into equation D to solve the system of equations? 4b + 5 6b − 2 4b 6b

Answer 1

a = 4b +5
a = 6b - 2

So, that means
4b +5 = 6b - 2
because they all equal to value a.

Also, this way you can solve the system of equation because they only have one undefined variable.

So, the answer is 4b +5

Answer 2

the answer is 4b +5

Explanation:

a = 4b +5 ------------> first equation

a = 6b - 2 ------------> second equation

Given the first equation a= 4b +5

Here 'a' is alone

In substitution method we substitute the first equation in second equation

So we substitute a= 4b+5 in the place of 'a' in second equation

The value 4b+5 can be substituted in the second equation to solve the system of equations