Question

The perimeter of a triangle is 147 inches. If one side of the triangle is five more than the shortest side, and the longest side is 16 more than the shortest side, find the lengths of the three sides?

Answer 1

The shortes side is x.
One side is five more than the shortest side, so it's x+5.
The longest side is 16 more than the shortest side, so it's x+16.
The perimeter, or the sum of all sides, is 147.


`x+x+5+x+16=147 \\ 3x+21=147 \\ 3x=147-21 \\ 3x=126 \\ x=(126)/(3) \\ x=42 \\ \\ x+5=42+5=47 \\ \\ x+16=42+16=58`

The lengths of the three sides are 42 in, 47 in, and 58 in.