Question

Jake, Tayo, and Blizzard have a combined age in dog years of 91. Tayo is 14 years younger than Jake. Blizzard is 6 years older than Jake. What is Jake's age,j, in dog years?

Answer 1

Let's assign variables to represent the ages of Jake, Tayo, and Blizzard in dog years.

Let:

Jake's age = j (in dog years)

Tayo's age = t (in dog years)

Blizzard's age = b (in dog years)

According to the given information, we have the following equations:

1) j + t + b = 91 (the combined age in dog years is 91)

2) t = j - 14 (Tayo is 14 years younger than Jake)

3) b = j + 6 (Blizzard is 6 years older than Jake)

We can solve this system of equations to find the value of j.

Substituting equations 2 and 3 into equation 1, we get:

j + (j - 14) + (j + 6) = 91

Simplifying the equation:

3j - 8 = 91

Adding 8 to both sides:

3j = 99

Dividing both sides by 3:

j = 33

Therefore, Jake's age in dog years is 33.

Answer 2

use placeholders

j=jake's age
t=tayo's age
b=blizzard's age

j+t+b=91

t is 14 younger than j
t=-14+j
t=j-14


b is 6 more than j
b=6+j



j+t+b=91
t=j-14
b=6+j
subsitute j-14 for t in first equation and 6+j for b in first equation
j+j-14+6+j=91
3j-8=91
add 8 to bot sides
3j=99
divide by 3
j=33
sbsitute

b=6+j
b=6++33
b=39


t=j-14
t=33-14
t=19



j=33
t=19
b=39




jakes arge=33