Question

Find the perimeter of triangle ABC, with coordinates A(-3, 0), B(0, 4), and C(3, 0).

a. 60
c. 16
b. 15
d. 30

Answer 1

Answer: it is sixteen, have a nice day! :-)

Answer 2

The perimeter is the sum of the lengths of all sides.
Find the lengths of the sides using the distance formula:

`d=√((x_2-x_1)^2+(y_2-y_1)^2) \\ \\ \\ A=(-3,0), B=(0,4), C=(3,0) \\ \\ |AB|=√((0-(-3))^2+(4-0)^2)=√(3^2+4^2)=√(9+16)=√(25)=5 \\ \\ |AC|=√((3-(-3))^2+(0-0)^2)=√(6^2+0^2)=√(6^2)=6 \\ \\ |BC|=√((3-0)^2+(0-4)^2)=√(3^2+(-4)^2)=√(9+16)=√(25)=5 \\ \\ P=|AB|+|AC|+|BC|=5+6+5=16`

The answer is c. 16.