Find the equation of the line that passes through (-2, -11) and is PERPENDICULAR to x + 4y = 8
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Line equations
y = mx+b
The slope is m
y-y1= m(x-x1)
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The point (x1, y1) = (-1, -11)
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Replacing
y- (-11)= m(x- (-1))
y + 11 = m (x +1)
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To determine the slope we use the information given,
PERPENDICULAR to x + 4y = 8
The result of multiplying the slopes of two perpendicular lines is -1
x + 4y = 8
4y = -x + 8
y = (-1/4) x + 2
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m1* m2 = -1
if m1 = -1/4
m2= -1/ (-1/4)
m2 = 4
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Replacing
y + 11 = m2 (x +1)
y + 11 = 4(x +1)
y = 4x + 4 -11
y = 4x -7
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Answer: y = 4x -7 or (y + 11) = 4(x +1)