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Find the midpoint of the line segment whose endpoints are (0, 1/2) and (0, 3/4). (0, 2/3) (0, 5/8) (0, 1 1/4)

User AstroSharp
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2 Answers

2 votes

Answer:

(0, 5/8)

Explanation:

User C Hogg
by
8.0k points
5 votes

A\ midpoint\ of\ the\ segment\ AB\ where\ A(x_A;\ y_A)\ and\ B(x_B;\ y_B):\\\\M_(AB)\left((x_A+x_B)/(2);\ (y_A+y_B)/(2)\right)\\-----------------------\\\\A(0; (1)/(2))\to x_A=0\ and\ y_A=(1)/(2)\\\\B(0;\ (3)/(4))\to x_B=0\ and\ y_B=(3)/(4)\\\\therefore\\\\M_(AB)\left((0+0)/(2);\ ((1)/(2)+(3)/(4))/(2)\right)=\left((0)/(2);\ ((1\cdot2)/(2\cdot2)+(3)/(4))/(2)\right)=\left(0;\ ((2)/(4)+(3)/(4))/(2)\right)


=\left(0;\ ((2+3)/(4))/(2)\right)=\left(0;\ ((5)/(4))/(2)\right)=\left(0;\ (5)/(4):2\right)=\left(0;\ (5)/(4)\cdot(1)/(2)\right)=\boxed{\left(0;\ (5)/(8)\right)}
User Richlv
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