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Use long division to find the quotient. (x²+6x-27) ÷ (x-3)
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Use long division to find the quotient. 

(x²+6x-27) ÷ (x-3)

User Shahrooz Ansari
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( x^2+6x-27 )/(x-3) = ( x^2+6x +3x-3x-27 )/(x-3) = ( x^2+9x-3x-27 )/(x-3) = \\ \\ =( x(x +9 )-3(x+9) )/(x-3) = ( (x +9 ) (x-3) )/(x-3) = x+9 \\ \\ \\ x-3\\eq 0 \\x\\eq 3\\D=R\setminus \left \{ 3 \right \}


User Vicsz
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