Question

Factor the expression completely. (If the expression is not factorable using integers, enter PRIME.)

ae + bf + af + be

I figured it out...
(a+b)(e+f)

Answer 1

(a + b)(e + f)
a(e + f) + b(e + f)
a(e) + a(f) + b(e) + b(f)
ae + af + be + bf

Answer 2

First you have to put like terms together:
bf+af+be+ae
Now you factor the first two terms and then the two last terms:
f(b+a)+e(b+a)
Now you factor even further. By putting what is in parentheses by what is outside the parentheses:
(b+a)(f+e)
What you got is correct as mine is too. I hope this formula helps for future problems:
ax+bx+ac+bc=x(a+b)+c(a+b)
=(a+b)(x+c)