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Make k the subject for 3t = 7k/13 - 17 and 7k = 4k/3t - 11t
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Make k the subject for 3t = 7k/13 - 17 and 7k = 4k/3t - 11t

User Jakube
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1 Answer

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3t = (7k)/(13) - 17 \\3t(1(6)/(7)) = 1(6)/(7)((7k)/(13) - 17) \\5(4)/(7)t = k - 31(4)/(7) \\(-k)/(-1) = (-5(4)/(7) - 31(4)/(7))/(-1) \\k = 5(4)/(7) + 31(4)/(7)


(7k)/(7) = ((4k)/(3t) - 11t)/(7) \\k = (4k)/(21t) - 1(4)/(7)
User Nitesh Verma
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