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1 vote
Calculate freezing temperature of.5 M sodium chloride solution. Assume that the molality of each solution is .5 M

a. -.93 Celsius
b. -1.86 Celsius
c. -3.72 Celsius
d. -.538 Celsius

User StarsSky
by
8.2k points

1 Answer

4 votes
Given,
Molality = .5M

We know, Kf = 1.86

Now,
Δ T = M x Kf
= 1.86 * 0.5
= 0.93 °C

Now,
Freezing point = Initial freezing point - Δ T
= 0°C - 0.93°C
= -0.93°C
So, the answer is A


User Keenan Thompson
by
7.6k points
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