Answer is: the sample is 232 years old.
Take 100 atoms:
After first half-life: 50% · 100 ÷ 100% = 50.
After second half-life: 0.5 · 50 = 25.
After third half-life: 0.5 · 25 = 12.5.
After fourth half-life: 0.5 · 12.5 = 6.25.
6.25 ÷ 100 · 100% = 6.25%.
4 half-lives will it take before only about 6.25% of the original sample remains.
t = 4 · 58 y.
t = 232 y.