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How many moles of water will be generated during the combustion of 0.38 moles of methyl alcohol (CH3OH)? 2CH3OH + 3O2 2CO2 + 4H2O
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How many moles of water will be generated during the combustion of 0.38 moles of methyl alcohol (CH3OH)? 2CH3OH + 3O2 2CO2 + 4H2O

User Kannan Arumugam
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2 Answers

3 votes

Answer:

0.76 moles

Step-by-step explanation:

User Thomas Bouldin
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8.2k points
2 votes
You already got the balanced equation. So the ratio of mole number is the ratio of the coefficient. Then the ratio of methyl alcohol and water is 2:4=1:2. The water generated is 0.38*2=0.76 mol.
User Sastraxi
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