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Given a solution with a Ph of 2.8, what is the [H3O+] of the solution?

User Wenzeslaus
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pH=-\log_(10) [H_3O^+] \Rightarrow [H_3O^+]=10^(-pH) \\ \\ pH=2.8 \\ \ [H_3O^+]=10^(-2.8) \approx 1.58 * 10^(-3)

The [H₃O⁺] of the solution is approximately 1.58 × 10⁻³ M.