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write the equation of a line that passes through the points (−3, 5) and (2, 10) in slope-intercept form

User Fgalan
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1 Answer

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Slope-intercept form y = mx + b

where m------> slope

b-------> y-intercept

m= (y1-y2)/(x1-x2)

P1(-3,5) (x1,y1)

P2(2,10) (x2,y2)

m= (5-10)/(-3-2)

m= (-5)/(-5)

m=1

Until now, the equation is y=mx+b

y=1.x+b

y=x+b

But, whe can plug the point P2(2,10) in y =x+b

10 =2 + b

10 - 2 = b

b= 8

Then, the equation is y=mx+b

y= x+8 <-------------------Solution

Verification P1(-3,5) y = x+8 5=-3+8 Ok

P2(2,10) y = x +8 10 = 2+8 Ok

User Abdelalim Hassouna
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