Question

If the point(x,√3/3)is on the unit circle, what is x?

Answer 1

The equation of the unit circle:

`x^2+y^2=1`


`(x,y)=(x, (√(3))/(3)) \\ \\ x^2+((√(3))/(3))^2=1 \\ x^2+(3)/(9)=1 \\ x^2+(1)/(3)=1 \\ x^2=1-(1)/(3) \\ x^2=(3)/(3)-(1)/(3) \\ x^2=(2)/(3) \\ x=\pm \sqrt{(2)/(3)} \\ x=\pm (√(2))/(√(3)) \\ x=\pm (√(2) * √(3))/(√(3) * √(3)) \\ x=\pm (√(6))/(3)`

x is equal to
`-(√(6))/(3)` or
`(√(6))/(3)`.