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If the point(x,√3/3)is on the unit circle, what is x?

User Aung Thiha
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1 Answer

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The equation of the unit circle:

x^2+y^2=1


(x,y)=(x, (√(3))/(3)) \\ \\ x^2+((√(3))/(3))^2=1 \\ x^2+(3)/(9)=1 \\ x^2+(1)/(3)=1 \\ x^2=1-(1)/(3) \\ x^2=(3)/(3)-(1)/(3) \\ x^2=(2)/(3) \\ x=\pm \sqrt{(2)/(3)} \\ x=\pm (√(2))/(√(3)) \\ x=\pm (√(2) * √(3))/(√(3) * √(3)) \\ x=\pm (√(6))/(3)

x is equal to
-(√(6))/(3) or
(√(6))/(3).
User Eternal Learner
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