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Solve for both systems: 2x + 5y = 24 and - 2x + 3y = 40
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Solve for both systems: 2x + 5y = 24 and - 2x + 3y = 40

User Sachin Ananthakumar
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\begin{cases} 2x+5y&=24(1)\\ -2x+3y&=40(2) \end{cases} (1)+(2) : 8y=64 \Rightarrow y=\frac{64}8=8\\(1) : x=\frac{24-5y}2=\frac{24-5\cdot8}2=-8 \\\boxed{x=-8,y=8}
User Magol
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Good Luckys...................
Solve for both systems: 2x + 5y = 24 and - 2x + 3y = 40-example-1
User Sam Rothstein
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