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1 vote
(78 n + 42)^2, when n = 91

1 Answer

5 votes
so evaluate/subsitue
the equation becomes
(78 times 91+42)^2

pemdas
do what's inside the parenthasees first

start over
parenthasees
exponents
multiplication and division yes 78 times 91
addition and subtraction so


78 times 91 is first
78 times 91=7098
addition
(7098+42)^2
(7140)^2

restart

parentasees simplified
exponents
7140^2=50,979,600
User Scott Offen
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