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Solve each problem by using the quadratic formula. Write solutions in simplest radical form. 2x2 + 2x – 2 = 0

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2x^2+2x-2=0 \ \ \ \ \ |/ 2 \\ x^2+x-1=0 \\ \\ a=1 \\ b=1 \\ c=-1 \\ b^2-4ac=1^2-4 * 1 * (-1)=1+4=5 \\ \\ x=(-b \pm √(b^2-4ac))/(2a)=(-1 \pm √(5))/(2 * 1)=-(1 \pm √(5))/(2) \\ \boxed{x=-(1+√(5))/(2) \hbox{ or } x=-(1-√(5))/(2)}
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