40.1k views
4 votes
Three consecutive whole numbers are such that if they be divided by 5,3 and 4 respectively, the sum of the quotient is 40. What are the numbers?

User Crixo
by
7.8k points

1 Answer

5 votes

(x)/(5)+(x+1)/(3)+(x+2)/(4)=40\\ 12x+20(x+1)+15(x+2)=2400\\ 12x+20x+20+15x+30=2400\\ 47x=2350\\ x=50\\ x+1=51\\ x+2=52

Then umbers are 50,51,52
User Cozimetzer
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories