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What is the area of 79 and 1/3 - 11 + 518

User Andrey Sobolev
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1 Answer

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10 votes

Based on the figure, it is necessary to calculate the area of the bigger rectangle and the area of the smaller one. Next, it is necessary to subtract both areas to obtain the area of the place without pool.

Proceed as follow:

Area of the bigger rectangle:

A1 = (7)(11 1/3) = (7)(34/3) = 238/3

Area of the pool:

A2 = (2 1/3)(4 5/6) = (7/3)(29/6) = 203/18

A1 - A2 = 238/3 - 203/18 = 68.055 = 68 1/18

Hence, the area of the region without pool is 68 1/8 squared units

User Liyan
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