Final answer:
In a monohybrid cross, the chance of the dominant phenotype appearing in offspring is 3/4, reflecting the 3:1 ratio typical of dominant-recessive trait inheritance.
Step-by-step explanation:
In a monohybrid cross, the chance of the dominant phenotype showing up in one of the offspring is 3/4. This is because when true-breeding or homozygous individuals that differ for a certain trait are crossed, all of the offspring will be heterozygotes for that trait. If the traits are inherited as dominant and recessive, the Fâ offspring will exhibit a ratio of three dominant to one recessive. This results from the fact that homozygous dominant and heterozygous individuals are phenotypically the same when the dominant trait is expressed. A Punnett square representing a cross between heterozygotes for a single trait (Bb) would illustrate that about 75% of the offspring will exhibit the dominant trait. This conforms to the expected 3:1 ratio in monohybrid crosses for a dominant phenotype versus a recessive phenotype.