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Sally found that a solution of x = 2 was extraneous for her function. What would be a possible denominator in Sally's function?

User Shunji Lin
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2 Answers

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x=2 should work

yay so only follow thw answer above

User Asaph
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If you have a fraction, then the denominator (bottom) cannot equal 0, since it is impossible to divide by 0. Take a look at the function below.


y=(5)/(x-2)

If we plugged in 2 for x, we would end up with a denominator of 0, making x = 2 "extraneous."

(you can use this example to answer your question, with the denominator being x-2...any expression that evaluates to 0 when x = 2 would work)
User Adamconkey
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