Question

What is the prime factorization of 1,260 A. 2x2x3x3x5x7 b. 2x3x5x7 c. 4x5x7x9 d. 2x3x5x6x7

Answer 1

Let’s count every 4 as 2^2, and put the negative in front of the parentheses. The result would be -(2^2*2^2*2^2*2^2*2^1*2^2*2^2*2^2*2^2*2^2*2^2*2^2*2^1), or -2^(2+2+2+2+1+2+2+2+2+2+2+2+1), or -2^12, which would be -4096.

Answer 2

to find out the prime factorization of 1260 you need to "decompose" this number in prime numbers
first step i will divide the 1260 by numbers that I know it is divisible by (ends in 0 so it will be 10, sum of the digits is 9 so will be divisible by 3)
1260=126*10=9*14*10=3*3*2*7*2*5
i need to write the prime numbers in order
1260=2*2*3*3*5*7 is choice A