Question

What are the vertical asymptotes of the function f(x) = the quantity of 2 x plus 8, all over x squared plus 5 x plus 6?

Answer 1

Explanation:

Alright, lets get started.

The given rational function is :

`f(x)=(2x+8)/(x^2+5x+6)`

For finding the vertical asymptotes of a rational function, we must set the denominator equal to zero.

So, equaling denominator to zero :

`x^2 +5x+6 = 0`

factoring

`(x+3)(x+2)=0`

This will give two values of x

`x=-3, x=-2`

So, these two are vertical asymptotes : Answer

Hope it will help :)

Answer 2

You'd find the vertical asymptotes by seeing where the denominator equals zero; you can do so by factoring the denominator.
In this case, you can factor the denominator into (x+3)(x+2), so if you set each of those equal to zero you can find the equations of the vertical asymptotes (x=-3 and x=-2).