Question

Write the equation of a line with a slope of 3 and a y-intercept of 1. y = x + 3 y = 3x + 1 3x + y = 1 x + 3y = 1

Answer 1

Y=mx+b is the general equation of a line. M is the slop and b is the y-intercept. Therefore, y=3x+1

Answer 2

If you know the the slope and y-intercept of a line you can write its equation in slope-intercept form, which is written like this:
where is the slope and is the y-intercept
In this case, since the slope is 3 and the y-int. is 1, our equation must be

`\boxed{y=3x+1}`