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4. In 2002, Sam invested $115,000 in high risk stocks. The following is an exponential function to represent the value of the stocks at a specific time period. y = 115000(.82)18 Please enter the appropriate blanks: What is the initial value Is this growth or decay What is the growth or decay Rate What is the time period listed in the exponential function listed above years What is the value of the exponential function listed above Round your answer 2 decimal places.

User Itzy
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1 Answer

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Solution


y=115000(0.82)^(18)

What is the initial value

Initial value = 115000

Is this growth or decay

Since 0.82 <1 , decay

What is the growth or decay Rate

The decay rate is 0.82

What is the time period listed in the exponential function listed above years

t = 18

What is the value of the exponential function listed above


y=115000(0.82)^(18)=3231.08

Round your answer 2 decimal places.​

User TheWalker
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