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What is the specific heat of metal if its mass is 26.86g and it requires 418.6 J of heat energy to raise its temperature from 27.4 oC to 67.3°C?

1 Answer

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Formula: q=m*c*(change in T)
q= 418.6
m=26.86
c= X(unknown)
(Change in T)= (67.3-27.4 = 39.9)

Now you solve for X, I got .391.
So the specific heat of this certain metal is .391 j/gram C


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