Question

What is the change in temperature if 24g of water at 50°C absorbs 985 J of heat energy?

Answer 1

The formula is q=M*C*(Change in T)
q= 985 J
M= 24g
C= 4.186 j/gram (it's waters specific heat)
Change in T= X (unknown)

Once you solve for X, you should get 9.8, at least that's what I got.
So the change in temperature is 9.8 C.

Answer 2

`\Delta T=9.82^oC`

Step-by-step explanation:

Hello,

In this case, we consider such heat absorption as an energy inlet, that is why the temperature of the water will raise as shown below as a positive result is obtained, considering water's heat capacity as 4.18 J/(g*°C):

`Q=mCp\Delta T\\\Delta T=(Q)/(mCp)=(985J)/(24g*4.18(J)/(g^oC) )\\\\\Delta T=9.82^oC`

Best regards.