Question

What is the total energy released when

9.11 × 10^−31 kilogram of mass is converted into
energy?
(1) 2.73 × 10^−22 J (3) 9.11 × 10^−31 J
(2) 8.20 × 10^−14 J (4) 1.01 × 10^−47 J

Answer 1

I found (2).
Using
`E=m c^(2) =9.11* 10^(-31)* (3*10^(8) )^(2) =8.2* 10^(-14)J`

Answer 2

The correct answer is option 2,

The total energy released is
`8.20 * 10^(-14) J\\`

Step-by-step explanation:

As per Einstein theory of relativity,

`E = mc^2\\`

where

"E" is the energy produced by mass conversion

"m" is the mass converted

"c" speed of light

Substituting the given values in above equation we get -

`E = (9.11 * 10^(-31)) Kg * ( 3 * 10^(8) (m)/(s) )^2\\= 8.20 * 10^(-14) J\\`