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What are the roots of the equation x^2+4x-16=0
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What are the roots of the equation x^2+4x-16=0
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Feb 4, 2016
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What are the roots of the equation x^2+4x-16=0
Mathematics
high-school
Puzik
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Puzik
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x² + 4x - 16 = 0
x =
-(4) ± √((4)² - 4(1)(-16))
2(1)
x =
-4 ± √(16 + 64)
2
x =
-4 ± √(80)
2
x =
-4 ± 4√(5)
2
x = -2 ± 2√(5)
x = -2 + 2√(5) U x = -2 - 2√(5)
Horaciux
answered
Feb 6, 2016
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Horaciux
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OK so you need to use the quadratic formula with
a=1, b=4, c=-16.
−b±√b^2−4ac
x=
------------------
2a
−(4)±√(4)^2−4(1)(−16)
x=
-----------------------------
2(1)
−4±√80
x=
---------------
2
Your final answer is:
x=−2+2√5 or x=−2−2√5
Dave McClelland
answered
Feb 9, 2016
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Dave McClelland
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